using similar triangles, it is clear that if the tree is halfway to the stake, then it is half as tall as the building.
Assuming that the rope touches the top of the tree, that is.
the stake is at ground level. The rope also touches a tree that is growing halfway between the stake and the
building. If the tree is 38 feet tall, how tall is the building?
38 ft.
19 ft.
76 ft.
57 ft.
Assuming that the rope touches the top of the tree, that is.
Those with 38 in the word problem should choose 19
Those with 36 in the word problem should choose 18.
"Lmao"
Make sure to read the problem right.
1) C. 76 ft
2) B. AI=AK
3) B. (3,5)
4) B. II only
5) C. Median
6) D. C,A,B
7) B. 10 cm, 15 cm, 24 cm
8) D. 1<n<25
9) midsegment
10) equidistant
11) perpendicular
12) concurrent
You can find the 13, 14, and 15 on brainly, just put them in your own
words
16) 3<n<15
I just took the test so I know that the multiple choice answers are all
correct, but 16 hasn't been graded yet but I'm pretty sure that's the
answer. Good luck!
2.b
3.a
4.b
5.b
6.a
7.b
8.c
9.d
10.b
11. midsegment
12. equidistant
13. perpendicular
14. concurrent
on your own of the others
1. 76 ft.
2. BI=BK
3. (3,5)
4. I only
5. perpendicular bisector
6. AC, BC, AB
7. 6cm, 10cm, 9cm
8. m<D,m<E,m<F
9. It must be greater than 9 and less than 24
10. m<A = m<C
11. midsegment
12. equidistant
13. perpendicular
14. concurrent
Thats the best way I can put it I got 76 i might post test answers
They may not be the same answers for other people so I'm sorry if you get it wrong.
1. 76ft
2. Bl = bk
3. 5,5
4. 2 only
5. Median
6. Ac, bc, ab
7. 18cm, 12cm, 9PM
8. LK, LJ, JK
9. 1<n<25
10. <c
11- 14. Midsegment, equidistant, perpendicular line, concurrent.
15. X = 5
Idk the rest I'm sorry
1. B-18 ft
2. B-BI = BK
3. A-(5,5)
4. A-I only
5. A-altitude
6. A-Line AC; Line AB; Line BC
7. B-18cm, 12cm, 9cm
8. B-ml D, ml E, ml F
9. D-1<n<25
10. C-ml C<ml B<ml A
11-14 I just copied @anonymous, so I don't really know these answers. Sorry, but for sure the last question is 100% right.
NOTE!!!! These are my answers so when taking the test make it your own words so you won't get into trouble. :) Just helping, thanks!
15. To find the value of X. We will have to use the mid segment theorem with finding out the 'given'. With the line connected to the midpoints of the two sides of the triangles is parallel, moving to the third side also adds half of the third side. B is the midpoint of AC and D is the midpoint of CE, so that makes (midpoint B of AC) AB = AC and the (midpoint D of CE) ED = DC. Together its BD = 3x + 5 and AE = 4x + 20. To proof the value of x, ⇒ 1/2 AE = BD ⇒ 1/2 4x + 20 = 3x + 5 ⇒ 4x + 20 = 2(3x + 5) ⇒ 4x + 20 = 6x + 10 ⇒ 20 - 10 = 6x - 4x ⇒ 10 = 2x ⇒ 10/2 = x ⇒ 5 = x.
So, the value of x is 5.
16. GE = 6 and BG = 3. The point that the three medians of the triangle intersect is known as the centroid of a triangle. Given, G is the centroid and BE = 9, the centroid point G divides the segment BE in a ratio of 2, 1, such that GE is twice the length of BE. BG = 1/3*BE, BG = 1/3*9 = 3, and GE = 2/3*9 = 6. So that makes it to be, GE = 6 and BG = 3.
17. The measure of length FG is 14 units. From the given diagram, since Line DF bisects angle EDG, EF = FG. The given parameters is, EF = n + 9 and FG = 4n - 6 equating both expressions as: n + 9 = 4n - 6, n - 4n = -6 - 9, -3n = -15, and n = 5. That would make the measure of FG = 14.
18. A. circumcenter: the point of is intersecting the perpendicular bisectors. B. incenter: the point of intersection of angle bisectors. C. centroid: the point of intersects of the medians, and D. orthocenter: the point of intersecting lines containing the altitudes.
19. All the vertices of a triangle are equidistant from the circumcenter. In an acute-angled triangle, the circumcenter lies inside the triangle. In an obtuse-angled triangle, it lies outside of the triangle. The circumcenter lies at the midpoint of the hypotenuse side of a right-angled triangle.
20. If "I" is the incenter of the triangle ABC, then ∠BAI = ∠CAI, ∠BCI = ∠ACI, and ∠ABI = ∠CBI using the angle bisector theorem. The sides of the triangle are tangents to the circle, and that leaves EI = FI = GI = r which is known as the inradii of the circle or radius of the incircle.
Have a nice day!
@kakashi is right for me