When Pb-208 bombarded with Ni-64, a new element and six neutrons are produced. What isotope of the new element is produced by this reaction?

Question

Question 17 options:

Ds-266


Ds-272


Rf-266


Rf-272

I believe it is either rf- 272 or Ds-272 because i added 208+64, but I do not know how to find out the new name.

Answer 1

It's difficult to write subscripts and superscripts here so here is what I do.
The first number is the subscript(the atomic number) and the next number (on the right) is the superscript (the mass number). The sum of subscripts on the left must equal the sum of subscripts on the right; the sum of superscripgs on the left must equal the sum of superscripts on the right.
Here is what the problem tells you.
82Pb208 + 28Ni64 = yXx + 6 on1

So 82 + 28 = y + 6 and y = ?. That's the atomic number; look that up on the periodic table to identify the element X with that number.

Then 208 + 64 = z + 6. z = ? That's the mass number of element X.
I don't think either of your guesses is right.