Asked by Anonymous

A projectile, fired with unknown initial velocity, lands 18.4 s later on the side of a hill, 2740 m away horizontally and 469 m vertically above its starting point. (Ignore any effects due to air resistance.)
(a) What is the vertical component of its initial velocity?
m/s

(b) What is the horizontal component of its initial velocity?
m/s

(c) What was its maximum height above its launch point?
m

(d) As it hit the hill, what speed did it have and what angle did its velocity make with the vertical?
v = m/s
θ = °
Answered by mahmoud
A projectile fired
Answered by mahmoud
A projectile fired with an know initial velocity lands 20s later on the side of a hill 3000m away horizontally and 450m vertically above its strating point . Find the horizontal and vertical components of its initial velocity
Answered by mahmoud
A projectile fired with an know initial velocity lands 20s later on the side of a hill 3000m away horizontally and 450m vertically above its strating point . Find the horizontal and vertical components of its initial velocity
Answered by Sami
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Answered by Sami
Gghh
Answered by aman
t=18.4 s later
x=740 m
H=469 m
v*2=u*2+2gh....at hmax , Vy =0
0=u*2+2gh
usina=radical 20(469)=96.8
horizontal componet of velocity
ucosa=x/t=740/18.4=40.21
Answered by Teme dawit
27. A projectile, fired with unknown initial velocity, lands 20 s later on the side of a hill, 3000

maway horizontally and 450 m vertically above its starting point. (a) What is the vertical

component of its initial velocity? (b) What is the horizontal component of its initial.

velocity?
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