Asked by Anonymous

A proposed space station includes living quarters in a circular ring 50.5 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth?
Answered by DonHo
v^2/r=g (mass doesn't matter)

v^2 = r*g

v = sqrt(r*g)
v= sqrt(50.5*9.81)

Answered by Damon
v^2/r =omega^2 r = g = 9.81 m/s^2

omega^2 = 9.81/50.5 (radians/sec)^2
Answered by Damon
What DonHo wrote is correct, but it asks for omega, the angular speed
Answered by DonHo
sorry, my formula is off

should be

v^2*r=g

v=sqrt(g/r)
Answered by Damon
Ac = omega^2 R = V^2/R
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