Asked by Jelon
The fifth term of an arithmetic series is 12 and the eighth term is 3. Find the sum of the first 6 terms and also of the first 11 terms.
T5=a+4d=12
T8=a+7d=3
-3d=9
d=-3
T5=a+4d=12
T8=a+7d=3
-3d=9
d=-3
Answers
Answered by
Jelon
answer is a=24
d=-3
6 term=9
11 terms = -6
d=-3
6 term=9
11 terms = -6
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