Asked by DEANA
The decomposition of potassium chlorate (KClO3) is used as a source of oxygen in the laboratory. How much potassium chlorate is needed to produce 10.2 mol of oxygen? Answer in units of mol
Answers
Answered by
laila
15.3 mol
Answered by
DrBob222
Laila is El wrongo! Used the factor upside down to get 15.3.
2KClO3 ==> 2KCl + 3O2
mols KClO3 = mols O2 x (2 mols KClO3/3 mols O2) = 10.2 x (2/3) = ?
2KClO3 ==> 2KCl + 3O2
mols KClO3 = mols O2 x (2 mols KClO3/3 mols O2) = 10.2 x (2/3) = ?
Answered by
Mr.RightisWrong
2KClO3 ==> 2KCl + 3O2
mols KClO3 = mols O2 x (2 mols KClO3/3 mols O2) = 10.2 x (2/3) = ?
mols KClO3 = mols O2 x (2 mols KClO3/3 mols O2) = 10.2 x (2/3) = ?
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