Asked by HAY

A solution with a pH of 7 has a [OH1-] of
Answered by DrBob222
pH + pOH = pKw = 14. You know pKw and pH, solve for pOH.
Then pOH = -log(OH^-)
Solve for OH^-
Answered by lll
7M. Is that correct?
Answered by DrBob222
no. pOH is 7 (but not molar).
pH + pOH = 14
pH = 7; therefore, pOH = 7
Now do pOH = -log(OH^-) and solve for OH^-
Answered by HAY
1 x 10-7 M?? Is that correct?
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