Asked by LADO
A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1065 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.62 hours with a standard deviation of 0.51 hour.
(1)Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating/drinking each day.
(A)The nutritionest is 95% confident that the mean amount of time spent eating or drinking per day for any is between ___, and____ hours.
(1)Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating/drinking each day.
(A)The nutritionest is 95% confident that the mean amount of time spent eating or drinking per day for any is between ___, and____ hours.
Answers
Answered by
PsyDAG
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.025) and its Z score.
95% = mean ± 1.96 SEm
SEm = SD/√n
95% = mean ± 1.96 SEm
SEm = SD/√n
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.