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A 0.205 g sample of impure NaOH requires 17.5 mL of 0.2180 M HCl for neutralization. What is the percent of NaOH in the sample, by weight?
10 years ago

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bobpursley
moles acid=.2180*.0175

mass NaOH=formulamassNaOH*molesacid
mass NaOH=40*moles acid above

percent= massNaOH/.205
10 years ago
Kate
Thank you! That makes much more sense.
10 years ago

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