Asked by Kate

A 0.205 g sample of impure NaOH requires 17.5 mL of 0.2180 M HCl for neutralization. What is the percent of NaOH in the sample, by weight?
Answered by bobpursley
moles acid=.2180*.0175

mass NaOH=formulamassNaOH*molesacid
mass NaOH=40*moles acid above

percent= massNaOH/.205
Answered by Kate
Thank you! That makes much more sense.
There are no AI answers yet. The ability to request AI answers is coming soon!