Asked by Steve

When a 1.50 kg block is 3.96 m above the base of the hill, the mass has a speed of 1.71 m/s. When the block reaches a point 0.750 m above the base of the hill, what is its kinetic energy?
Answered by bobpursley
KE gain= gpe loss
ke gain =m*g*(3.96-.750)
Answered by Anonymous
Searches related to A block is sliding down a frictionless hill. When the 1.50 kg block is 3.96 m above the base of the hill, the mass has a speed of 1.71 m/s. Determine the kinetic energy of the block when it is at a height of 0.750 m above the base of the hill.
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