total force? that is weight, plus horizontal force.
weight: 72*9.8 N
horizontal force= 72*(61/7.8) N
magnitude then= sqrt (weight^2+horizonal^2)
The acceleration of gravity is 9.8 m/s^2 . What is the magnitude of the total force on a(n) 72 kg driver by the dragster he operates as it accelerates horizontally along a straight line from rest to 61 m/s in 7.8 s? Answer in units of kN
4 answers
F=m*a
It only asks about the force from the dragster, so ignore gravity. F = 72*a
a = (Vf-Vo)/t
a=61/7.8
F = (72)(71/7.8)
It only asks about the force from the dragster, so ignore gravity. F = 72*a
a = (Vf-Vo)/t
a=61/7.8
F = (72)(71/7.8)
I would like to agree, but there is a force from the table on the dragster wupward supporting weight, so it can go horizonatally.....
Vinny I'm sorry to do this to someone who shares my name but bob is right ;3
2 answers