Question

The acceleration of gravity is 9.8 m/s^2 . What is the magnitude of the total force on a(n) 72 kg driver by the dragster he operates as it accelerates horizontally along a straight line from rest to 61 m/s in 7.8 s? Answer in units of kN

Answer 1

total force? that is weight, plus horizontal force.

weight: 72*9.8 N
horizontal force= 72*(61/7.8) N

magnitude then= sqrt (weight^2+horizonal^2)

Answer 2

F=m*a

It only asks about the force from the dragster, so ignore gravity. F = 72*a

a = (Vf-Vo)/t

a=61/7.8

F = (72)(71/7.8)

Answer 3

I would like to agree, but there is a force from the table on the dragster wupward supporting weight, so it can go horizonatally.....

Answer 4

Vinny I'm sorry to do this to someone who shares my name but bob is right ;3