a car is running at 50 mph when the driver starts to step at the breaks. if the car decelerates at the rate of 7 ms^2, how long does it take the car stop?

1 answer

Vo = 50mi/h * 1600m/mi * 1h/3600s. = 22.22 m/s.

V = Vo + a*t = 0 When stopped.
t = -Vo/a = -22.22/-7=3.17 s. To stop.