Asked by joy
A sample of gas in a balloon has an initial temperature of 9.0∘C and a volume of 1.75×103L . If the temperature changes to 80.∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?
Answers
Answered by
joy
87
Answered by
MathMate
Not sure how you got 87! :)
Start with PV/T=constant, where T is in °K.
V1=1.75*10³L
T1=(9.0+273.15)=282.15°K
T2=(80+273.15)=353.15°K
(ok to use excess significant digits for calculation, but reduce answer to appropriate number).
since Pressure & amount of gas remain constant, we have
V/T=constant, or
V1/T1=V2/T2
=>
V2=V1(T2/T1)
=1.75*10³(353.15/282.15)
=2.19*10³ L
Start with PV/T=constant, where T is in °K.
V1=1.75*10³L
T1=(9.0+273.15)=282.15°K
T2=(80+273.15)=353.15°K
(ok to use excess significant digits for calculation, but reduce answer to appropriate number).
since Pressure & amount of gas remain constant, we have
V/T=constant, or
V1/T1=V2/T2
=>
V2=V1(T2/T1)
=1.75*10³(353.15/282.15)
=2.19*10³ L
Answered by
CeCe
Not sure how you got 87 as well. However, 2.19*103L or 2190 L is correct!
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