Asked by Zoe
Determine exact solution. x E (0, 2pi)
2csc^2x-8=0
2csc^2x-8=0
Answers
Answered by
Reiny
2csc^2x-8=0
csc^2 x = 4/2 = 4
then
sin^2 x = 1/4
sinx = ±1/2 ---> so x can be in any of the 4 quads
we know sinπ/6 = 1/2
so
x = π/6
x = π - π/6 = 5π/6
x = π + π/6 = 7π/6
x = 2π - π/6 = 11π/6
csc^2 x = 4/2 = 4
then
sin^2 x = 1/4
sinx = ±1/2 ---> so x can be in any of the 4 quads
we know sinπ/6 = 1/2
so
x = π/6
x = π - π/6 = 5π/6
x = π + π/6 = 7π/6
x = 2π - π/6 = 11π/6
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