Asked by Anonymous

calculate the molar hydroxide ion concentration of each of the following solutions given the pH 4.53. Answer should be for OH-.

Please show me how to do this in step by step
Answered by Antonie
pOH = 14 - pH

therefore, ur pOH will be = 14 - 4.53
= X (suppose)

pOH = -log[OH^-]
X = -log[OH^-]

Solve for [OH^-]
Answered by Anonymous
OH=9.47
-log= 0.976349979

is this correct
Answer
okay correct.....so the 9.47 is correct...then you put in your calculator -9.47 2nd log to get 3.388441561 -10, which is rounded off to 3.4 * 10^-10
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