Asked by wally

1/(X+3)+4/(x+5)= 2/(x^2+8x+15)


a. the solution set is
b. the solution set is all real numbers
c. the solution set is empty
Answered by Reiny
Did you notice that x^2 + 8x + 15 = (x+3)(x+5) which happen to be the denominators on the left side

So let's multiply everybody by (x+3)(x+5)
(x+5) + 4(x+3) = 2

Now how easy is that from there ?
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