Breaking strength
T=mg=33.8kg*9.8 N
mass = 3.02 kg
radius = 1.2 m
velocity = v
Tension on string
S=mv²/r=3.02*v²/1.2
At breaking point, S=T
3.02*v²/1.2 = 33.8*9.8
Solve for v. I get 11.5 m/s
A 3.02 kg mass attached to a light string
rotates on a horizontal, frictionless table. The
radius of the circle is 1.2 m, and the string can
support a mass of 33.8 kg before breaking.
The acceleration of gravity is 9.8 m/s
2
.
What maximum speed can the mass have
before the string breaks?
Answer in units of m/s
1 answer
2 answers