Asked by May
Elephants communicate via infrasound, at frequencies as low as 14 Hz that can travel up to 10 km. The intensity of these sounds can reach 103 dB, measured a distance of 5.0 m from the source. Determine the intensity level of the infrasound 10 km from the source, assuming the sound energy radiates uniformly in all directions.
Answers
Answered by
Damon
I2/I1 = R1^2/R2^2 = 5^2/(10^4)^2
= 25 * 10^-8
10 log (25*10^-8) = 10 [-8 + 1.4]
= - 66 dB
103 - 66 = 37 dB
still pretty loud
= 25 * 10^-8
10 log (25*10^-8) = 10 [-8 + 1.4]
= - 66 dB
103 - 66 = 37 dB
still pretty loud