Asked by sanjana singhania
The speeds of two trains A and B are in the ratio of 5:6. A takes 36 minutes more than B to reach the destination.what is the time taken by A to reach the destination to cover the same distance?
Answers
Answered by
Henry
B: X min.
A: (X+36) min.
A/B = (x+36)/x = 6/5
5x + 180 = 6x
5x - 6x = -180
-X = -180
X = 180 min.
X+36 = 180+36 = 216 min.
A: (X+36) min.
A/B = (x+36)/x = 6/5
5x + 180 = 6x
5x - 6x = -180
-X = -180
X = 180 min.
X+36 = 180+36 = 216 min.
Answered by
kam
The speeds of two trains A and B are in the ratio of 5:6. A takes 30 minutes more than B to reach the destination.what is the time taken by A to reach the destination to cover the same distance?
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