The angular velocity of a wheel is given by w(t) = (2.00 rad/s^2)t + (1.00 rad/s^4)t^3.

A. What is the angular displacement of the wheel from time t=0.00s to time t=T?

B.What is the angular acceleration of the wheel as a function of time?

1 answer

ω(t)=t³+2t rad/s
note that ω(0)=0 rad/s.

(A)
Angular displacement
=∫ω(t)dt [0≤t≤T]
=[t^4/4+t^2] from 0 to T
=T^4/4 + T²

(B)
The angular acceleration is obtained by differentiation of ω(t) with respect to t.