Asked by Jack
A 0.118 kg baseball traveling with a horizontal speed of 3.14 m/s is hit by a bat and then moves with a speed of 33.7 m/s in the opposite direction. What is the magnitude of the change in the ball's momentum?
Answers
Answered by
MathMate
Momentum = mass*velocity
Note that velocity is <i>signed</i>.
Using
subscript 1=before impact
subscript 2=after impact.
Here, mass=0.118 kg=m1=m2
v1=+3.14 m/s (towards bat)
v2=-33.7 m/s (away from bat)
Calculate the change in momentum,
Δmomentum = m2v2-m1v1
and give answer in absolute value (magnitude).
Note that velocity is <i>signed</i>.
Using
subscript 1=before impact
subscript 2=after impact.
Here, mass=0.118 kg=m1=m2
v1=+3.14 m/s (towards bat)
v2=-33.7 m/s (away from bat)
Calculate the change in momentum,
Δmomentum = m2v2-m1v1
and give answer in absolute value (magnitude).
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