Calculate the pH of a 1.19M sodium formate, HCOONa, solution.

Answer 1

Let's call formate ion for-. It will hydrolyze as follows:

.........for- + HOH ==> Hfor + OH^-
I........1.19.............0.....0
C.........-x..............x.....x
E.......1.19-x............x.....x

Kb for for- = (Kw/Ka for formic acid) = (x)(x)/(1.19-x)
Solve for x = OH^- and convert that to pH.