Asked by Catherine
How do you set up this problem? Calculate the volume , in ml of a 0.150 M NaOH soulution needed to neutralize 25.0ml of a 0.288 M HCl solution?
Answers
Answered by
Steve
Since each mole of HCl neutralizes 1 mole of NaOH,
.025L * .288M = 0.0072 moles HCl
So, for the NaOH,
0.0072 moles / 0.150M = .048L or 48 ml
.025L * .288M = 0.0072 moles HCl
So, for the NaOH,
0.0072 moles / 0.150M = .048L or 48 ml
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