Question
What volume of 0.140 M K2Cr2O7 will be required to oxidize the Fe2+ ion in 81.5 mL of 0.176 M FeSO4 solution?
Cr2O72- + Fe2+ Cr3+ + Fe3+ (acid solution)
Cr2O72- + Fe2+ Cr3+ + Fe3+ (acid solution)
Answers
DrBob222
Find your arrow key and use it.
1. Balanced the equation.
2. mols Fe^2+ = M x L = ?
3. Using the coefficients in the balanced equation, convert mols Fe(II) to mols Cr2O7^2-.
4. Then M Cr2O7^2- = mols/L. You have M and mols, solve for L, convert to mL if you wish.
1. Balanced the equation.
2. mols Fe^2+ = M x L = ?
3. Using the coefficients in the balanced equation, convert mols Fe(II) to mols Cr2O7^2-.
4. Then M Cr2O7^2- = mols/L. You have M and mols, solve for L, convert to mL if you wish.