Asked by fatima

A certain reaction is spontaneous at 72˚C. if the enthalpy change for the reaction is 19Kj/mol, what is the minimum value of ΔS (in J/K•mol) for the reaction?
Answered by DrBob222
dG = dH - TdS
Max value for dG is 0.
Then TdS = dH
dS = dH/T = 19,000/(273+72)
dS = ?
Answered by Anonymous
55 J/K