You are unloading a refrigerator from a delivery van. The ramp on the van is 5.0m long and its top end is 1.4m above the ground. As the refrigerator moves down the ramp, you are on the downside of the ramp trying to slow the motion by pushing horizontally against the refrigerator with a force of 300N.
How much work do you do on the refrigerator during its trip down the ramp?
3 answers
-1440 J
a^2 + b^2 = c^2
a = sqrt(c^2 - b^2)
a=4.8
work is done in the direction of the 4.8 distance but opposes movement, so it will be negative.
4.8*-300 = -1440
a = sqrt(c^2 - b^2)
a=4.8
work is done in the direction of the 4.8 distance but opposes movement, so it will be negative.
4.8*-300 = -1440
work = f x
w = 300(-5) = -1500 J
w = 300(-5) = -1500 J
1 answer