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A 0.504 m length of conducting wire carrying a current of 62.1 A is?
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Length of current carrying wire l = 0.504 m
Current through wire i = 62.1 A
Consider perpendicular external magnetic field with magnitude 0.203 T.[ Not given in problem , so we considered ]
External magnetic field is perpendicular θ = 90º
Magnetic field of magnitude B = 0.203 T.
The magnitude of the magnetic force on this wire is F = Bilsinθ
F = (0.203)(62.1)(0.504)sin(90) = 6.3536 N
The magnitude of the magnetic force on this wire is 6.3536 N.
Current through wire i = 62.1 A
Consider perpendicular external magnetic field with magnitude 0.203 T.[ Not given in problem , so we considered ]
External magnetic field is perpendicular θ = 90º
Magnetic field of magnitude B = 0.203 T.
The magnitude of the magnetic force on this wire is F = Bilsinθ
F = (0.203)(62.1)(0.504)sin(90) = 6.3536 N
The magnitude of the magnetic force on this wire is 6.3536 N.
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