Asked by huma
To take a taxi in downtown, it will cost you $3.00 to go a mile. After 6 miles, it will cost $5.25. The cost varies linearly with the distance traveled. Write the equation expressing cost (c) in terms of miles (d) traveled.
Answers
Answered by
Derius
c is cost and d is miles traveled? K.
c = 3 + .45d.
Based on the wording, it appears it cost 3 dollars for the first mile and .45 for the next 5 bringing the total to 5.25 for 6 miles.
So $3 is the base, or the constant, and each additional mile is 45 cents.
c = 3 + .45d.
Based on the wording, it appears it cost 3 dollars for the first mile and .45 for the next 5 bringing the total to 5.25 for 6 miles.
So $3 is the base, or the constant, and each additional mile is 45 cents.
Answered by
Deb
How is this the solution if 3 + .45d does NOT equal the cost of $5.25 when the taxi is used for the 6 miles? Check your solution please. The proper solution is given by the following equation: C(d) = .45d + 2.55 and is found by taking the $3 constant cost for the 1 mile + .45 slope TIMES (miles driven OVER the 1 mile...expressed as (d - 1) After simplifying...you get solution...so...
C(d)= 3 + ,45(d-1) which is 3+.45d-.45
which then becomes... .45d + 2.55
C(d)= 3 + ,45(d-1) which is 3+.45d-.45
which then becomes... .45d + 2.55
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