Asked by Rachel
How would i determine the values of 'k' if the graph y=2x^2-2x+3k intersects the x-axis at two distinct points?
Answers
Answered by
Dr Russ
This is similar ot the other problem.
If the equation crosses the x-axis then y=0.
So you need to find the solutions for
0=2x^2-2x+3k
using the general equation we get
x=-2+/-(4-4.2.3k)^.5/4
for there to be real values
4-24k>0 (we can't square root a number less than zero, and it can't equal zero as the question says there are two distinct points. Zero would give us two coincident points)
so 4>24k or k<4/24 k<0.1667
Check my working!
If the equation crosses the x-axis then y=0.
So you need to find the solutions for
0=2x^2-2x+3k
using the general equation we get
x=-2+/-(4-4.2.3k)^.5/4
for there to be real values
4-24k>0 (we can't square root a number less than zero, and it can't equal zero as the question says there are two distinct points. Zero would give us two coincident points)
so 4>24k or k<4/24 k<0.1667
Check my working!
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