Asked by Monteshia
In a volumetric analysis experiment, a solution of sodium oxalate (Na2C2O4) n acidic solution is titrated with a solution of potassium permanganate (KMnO4) according to the following balanced chemical equation:
2KMnO4(aq)+8H2SO4(aq)+5Na2C2O4(aq)-> 2MnSO4(aq)+8H2O(l)+CO(g)=5Na2SO4(aq)+K2SO4(aq)
M KMnO4 to reach the endpoint. What mass of Na2C2O4 was present intitially?
2KMnO4(aq)+8H2SO4(aq)+5Na2C2O4(aq)-> 2MnSO4(aq)+8H2O(l)+CO(g)=5Na2SO4(aq)+K2SO4(aq)
M KMnO4 to reach the endpoint. What mass of Na2C2O4 was present intitially?
Answers
Answered by
DrBob222
You didn't provide the molarity of KMnO4.
Step 1. You have the equation. I assume it is balanced.
Step 2. mols KMnO4 = M x L = ?
Step 3. Covert mols KMnO4 to mols Na2C2O4 using the coefficients in the balanced equation.
Step 4. Convert mols Na2C2O4 to grams. g =mols x molar mass
Step 1. You have the equation. I assume it is balanced.
Step 2. mols KMnO4 = M x L = ?
Step 3. Covert mols KMnO4 to mols Na2C2O4 using the coefficients in the balanced equation.
Step 4. Convert mols Na2C2O4 to grams. g =mols x molar mass
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