Question

Solve the equation. You will have three solutions.
X^3-8=0

Answer 1

x^3-8=0
+ +8
x^3=8

2^3=8
so one of the soulution is x=2

Answer 2

using the difference of cubes factoring

x^2 - 8 = 0
(x-2)(x^2 + 2x + 4) = 0
x = 2
or
x = (-2 ±√-12)/2
= (-1 ± 2√3 i )/2
= -1 ± √3 i

for 3 solutions, one real, two complex