Solve (16x^2)^-3/4

Question

Please help using step by step. I don't understand how to do this. Thank you

Answer 1

first , because of the negatiave outer exponent

= 1/(16x^2)^3/4

since (ab)^x = a^x * a^x

we get
1/( (16^(3/4 ) * x^(3/2)

now 16^(3/4) = (16^(1/4) )^3 = 2^3 = 8

so finally

= 1/(8 (√x)^3 )