Asked by Mahnoor
Suppose that 50.0 mL of a 0.250 M HCl solution is mixed with 50.0 mL of a 0.100 M
Ba(OH)2 solution in a coffee-cup calorimeter. The temperature of the resulting solution increases by
1.76 oC . Calculate DH for the reaction between HCl (aq) and Ba(OH)2 (aq) in kJ per mole of Ba(OH)2 reacted. Assume that the specific heat capacity of the resulting solution is 4.18 J/g oC and
that the density of the resulting solution is 1.00 g/mL . Also assume that the heat capacity of the
calorimeter itself can be ignored.
Ba(OH)2 solution in a coffee-cup calorimeter. The temperature of the resulting solution increases by
1.76 oC . Calculate DH for the reaction between HCl (aq) and Ba(OH)2 (aq) in kJ per mole of Ba(OH)2 reacted. Assume that the specific heat capacity of the resulting solution is 4.18 J/g oC and
that the density of the resulting solution is 1.00 g/mL . Also assume that the heat capacity of the
calorimeter itself can be ignored.
Answers
Answered by
DrBob222
If you expect to continue getting help you should show some work. Or something about how you would attack the problem. Or EXACTLY what you don't understand about the process.
Answered by
DrBob222
q = [mass H2O x specific heat H2O x delta T]
Then dH is q/mol Ba(OH)2 and convert to kJ.
Then dH is q/mol Ba(OH)2 and convert to kJ.
Answered by
y
175j
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