Asked by Anonymous
A 2.28 kg bucket is attached to a disk-shaped pulley of radius 0.104 m and mass 0.712 kg.
If the bucket is allowed to fall, calculate the tension in the rope.
If the bucket is allowed to fall, calculate the tension in the rope.
Answers
Answered by
Anonymous
M = 2.28kg
r = 0.104m
m = 0.712kg
T = ?
Torque = -Tr
Tension = - Iα / r = -1/2M(ay)
Fy: T - mg = may
T = may + mg
(m + M / 2)ay = -mg
ay = - g / (1 + m / 2M)
ay = -9.8 / [(1 + 0.712 / (2 * 2.28)]
ay = -8.48m/s²
T = M(g - a)
T = 2.28kg(9.8m/s² - 8.48m/s²)
T = 3.01N <-- Answer
r = 0.104m
m = 0.712kg
T = ?
Torque = -Tr
Tension = - Iα / r = -1/2M(ay)
Fy: T - mg = may
T = may + mg
(m + M / 2)ay = -mg
ay = - g / (1 + m / 2M)
ay = -9.8 / [(1 + 0.712 / (2 * 2.28)]
ay = -8.48m/s²
T = M(g - a)
T = 2.28kg(9.8m/s² - 8.48m/s²)
T = 3.01N <-- Answer
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