Asked by Aaqib Zaman
N2O5 is an unstable gas that decomposes according to the following reaction:
2N2O3(g) ---> 4NO2(g) + O2(g)
What would be the total pressure of gases present if a 10.0L container at 22.0 degree centigrade begins with 0.400 atm of N2O5 and the gas completely decomposes?
2N2O3(g) ---> 4NO2(g) + O2(g)
What would be the total pressure of gases present if a 10.0L container at 22.0 degree centigrade begins with 0.400 atm of N2O5 and the gas completely decomposes?
Answers
Answered by
DrBob222
You made a typo on the equation.
2N2O5 ==> 4NO2 + O2
When using gases one may use the gas pressure as if it were mols.
Convert atm N2O5 to atm NO2. That's 0.4 atom x (4 mols NO2/2 mols N2O5) = ? atm for NO2.
0.4 atm x (1 mol O2/2 mols N2O5) - ? atm for O2.
Add the two for Ptotal.
2N2O5 ==> 4NO2 + O2
When using gases one may use the gas pressure as if it were mols.
Convert atm N2O5 to atm NO2. That's 0.4 atom x (4 mols NO2/2 mols N2O5) = ? atm for NO2.
0.4 atm x (1 mol O2/2 mols N2O5) - ? atm for O2.
Add the two for Ptotal.
Answered by
Roanna
1 atm
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