Question
sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly
sin(2theta)
cos(2theta)
tan(2theta)
sin(2theta) would it be 2 x (8/17)
cos(2theta) would be 2 x (15/17)
tan(2theta) would be 2 x (8/17 divided by 15/17)
is this correct? I tried punching that into my homework for as an attempt and it comes back incorrect. Maybe I am not writing the exact answers correctly?
sin(2theta)
cos(2theta)
tan(2theta)
sin(2theta) would it be 2 x (8/17)
cos(2theta) would be 2 x (15/17)
tan(2theta) would be 2 x (8/17 divided by 15/17)
is this correct? I tried punching that into my homework for as an attempt and it comes back incorrect. Maybe I am not writing the exact answers correctly?
Answers
sinθ = 8/17 in QII means that
cosθ = -15/17
sin2θ = 2sinθcosθ = 2(8/17)(-15/17)
cos2θ = cos^2θ - sin^2θ = (15/16)^2 - (8/17)^2
tan2θ is of course, sin2θ/cos2θ
cosθ = -15/17
sin2θ = 2sinθcosθ = 2(8/17)(-15/17)
cos2θ = cos^2θ - sin^2θ = (15/16)^2 - (8/17)^2
tan2θ is of course, sin2θ/cos2θ
NNNNNNNNNNNNNNNOOOOOOOOOOOOOO
Related Questions
1)Find cos theta if sin theta=3/5 and 90 degrees<theta<180 degrees.
A)4/5
B)-4/5
C)square root of...
if cot theta =7/8 , evaluate (1+sin^2theta)(1-sin^2theta)/(1+cost^2theta)(1+co-^2theta)
the answe...
sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exact...
Solve tan(40/90) for the double angle cos(2theta). I know I use the x^2 + y^2 = r^2 formula and cos(...