Question

For a board game there is 3 kinds of bills. There are 11 more $2 bills than $1 dollar bills. There are 18 fewer $3 dollar bills than $1 bills. The total for the bill is $100. How many $1 bills are used?
100 = n+2(n -11)+3(n+18)
100= n-2n-22+3n +54
100 = 6n +76
24=6n 4=n

Answer 1

number of $1 --- n
number of $2 --- n+11
number of $3 --- n-18

now for the "value" :

1n + 2(n+11) + 3(n-18) = 100
n+2n+22 + 3n-54 = 100
6n = 132
n = 22

then n+11 = 33
n-18 = 4

so 22 $1 bills , 33 $2 bills and 4 $3 bills

check:
22 + 66 + 12 = 100
Yeahh