Asked by Trish Goal
I already posted this question,Steve answered it. I just wanted to clarify my answer.
Problem:Find h(x) with terms in order of decreasing degree,
if 9x^3-3x+1+h(x)=3x^2-5x+3.
Steve: h(x) = (3x^2-5x+3)-(9x^3-3x+1)
so, just subtract tghe coefficients of like powers.
My answer:−9x^3+3x^2−2x+2 so the answer would be −9x^3,3x^2,−2x right?
Problem:Find h(x) with terms in order of decreasing degree,
if 9x^3-3x+1+h(x)=3x^2-5x+3.
Steve: h(x) = (3x^2-5x+3)-(9x^3-3x+1)
so, just subtract tghe coefficients of like powers.
My answer:−9x^3+3x^2−2x+2 so the answer would be −9x^3,3x^2,−2x right?
Answers
Answered by
Reiny
h(x) = −9x^3+3x^2−2x+2
why did you put commas between terms in your answer ?
why did you put commas between terms in your answer ?
Answered by
Trish Goal
Because it is asking for the terms in order of decreasing degree.
Answered by
Reiny
in h(x) = −9x^3+3x^2−2x+2
they are in order of decreasing degree
they are in order of decreasing degree
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