h(x) = −9x^3+3x^2−2x+2
why did you put commas between terms in your answer ?
Problem:Find h(x) with terms in order of decreasing degree,
if 9x^3-3x+1+h(x)=3x^2-5x+3.
Steve: h(x) = (3x^2-5x+3)-(9x^3-3x+1)
so, just subtract tghe coefficients of like powers.
My answer:−9x^3+3x^2−2x+2 so the answer would be −9x^3,3x^2,−2x right?
why did you put commas between terms in your answer ?
they are in order of decreasing degree
To clarify the process, Steve correctly explained that to find h(x), you need to subtract the coefficients of like powers from the given equation. In this case, you are subtracting the coefficients of x^3, x^2, and x.
So, let's break down the subtraction step:
(3x^2 - 5x + 3) - (9x^3 - 3x + 1)
When subtracting, you can rearrange the terms in any order as long as you take care to keep the signs correct. So, let's rearrange the terms and group them by their corresponding powers of x:
(-9x^3 + 3x^2 - 5x - 3x + 1 - 3)
Now let's simplify each group of terms:
-9x^3 - 2x^2 - 8x - 2
Therefore, the final answer for h(x) would be -9x^3 - 2x^2 - 8x - 2.
You correctly identified the terms in decreasing degree order: -9x^3, 3x^2, -2x.
So, well done on clarifying your answer!