Question
verify that g(x)=3x sqrt(x-5) satisfies the condition of rolle's theorem on the interval [0,5]. Find all numbers c that satisfies rolles theorem.
Answers
g(0) is not defined, since sqrt(-5) is not real.
So, g(x) does not satisfy the condition that g(0) = 0
You want to reconsider any part of the question?
So, g(x) does not satisfy the condition that g(0) = 0
You want to reconsider any part of the question?
Sorry +5
In that case,
g(0) = 0
g(5) = 15√10
Again Rolle's Theorem does not apply. Try again.
g(0) = 0
g(5) = 15√10
Again Rolle's Theorem does not apply. Try again.
I think you want
g(x) = 3x√(x+5) on [-5,0]
g(-5) = 0
g(0) = 0
So, we want c somewhere in (-5,0) such that f'(c) = 0
f'(x) = 3(3x+10) / 2√(x+5)
f' = 0 when 3x+10 = 0
So, c = -10/3 which is in the domain.
g(x) = 3x√(x+5) on [-5,0]
g(-5) = 0
g(0) = 0
So, we want c somewhere in (-5,0) such that f'(c) = 0
f'(x) = 3(3x+10) / 2√(x+5)
f' = 0 when 3x+10 = 0
So, c = -10/3 which is in the domain.
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