How do I solve this using the Quadratic formula and finding the determinant?

Question

1. 5x-6=0
2. x+25=0

Answer 1

Neither equation you state is a quadratic equation

for the first, we could attempt to write it as
0x^2 + 5x - 6 = 0 , but when we attempt to use the formula x = (-b ± √(b^2 - 4ac) )/2a
we get x = (-5 ± √(25 - 0)/0
= 0/0 , which of course causes all kinds of problems

did you check that you typed it correctly ?

Answer 2

Step 1:

5x-6=0
+6 +6 Add the six to both sides

Step 2:
Then divide the five to both sides isolate the x

5x=6
/5 /5

Answer should be:

x=6/5

Then do the same to the second one and you should get

x=-25 if you did it right