Asked by Cory
In a triangle ABC, with angles A, B, and C and sides AB, BC, and AC, angle B is a right (90°) angle. If the sin of angle A is 0.5 and side BC is 8 inches long, what is the length of side AC?
Answers
Answered by
Cam
sin A = 1/2
A = 30 degrees
sin is opposite over hypotenuse thus, BC/AC
BC = 8 (given)
thus 1/2 = 8/AC
AC = 16
cos A is cos 30degrees so cos A = (sqrt(3)) / 2
cos is always adjacent over hypotenuse thus, AB/AC
because AC = 16
sqrt3 /2 = AB/16
AB = 8 sqrt3
A = 30 degrees
sin is opposite over hypotenuse thus, BC/AC
BC = 8 (given)
thus 1/2 = 8/AC
AC = 16
cos A is cos 30degrees so cos A = (sqrt(3)) / 2
cos is always adjacent over hypotenuse thus, AB/AC
because AC = 16
sqrt3 /2 = AB/16
AB = 8 sqrt3
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