Asked by Sally
Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). For my answer, I got "All Real Numbers" or x=0 but I'm not sure if that's right. Thanks a bunch! :)
Answers
Answered by
Henry
Log2(x+4) = Log2(x^2+2)
x + 4 = x^2 + 2
x - x^2 = 2 - 4
-x^2 + x = -2
-x^2 + x + 2 = 0
Multiply both sides by -1:
x^2 - x - 2 = 0
-2 = -2*1. Sum = -2 + 1 = -1 = B.
x+(-2)) = 0
x-2 = 0
X = 2
x+1 = 0
X = -1
Solution: X = -1, and 2.
x + 4 = x^2 + 2
x - x^2 = 2 - 4
-x^2 + x = -2
-x^2 + x + 2 = 0
Multiply both sides by -1:
x^2 - x - 2 = 0
-2 = -2*1. Sum = -2 + 1 = -1 = B.
x+(-2)) = 0
x-2 = 0
X = 2
x+1 = 0
X = -1
Solution: X = -1, and 2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.