Asked by Heather
Sorry there are quite a few problems, but I just need to know if these are correct (and if they aren't, where I went wrong):
1. Solve these equations.
tanθ = -√3
θ = 2π/3 + kπ
θ = 5π/3 + kπ
2. secθ = √2
θ = π/4 + 2kπ
θ = 7π/4 + 2kπ
3. tanθ = -√3/3
θ = 5π/6 + kπ
θ = 11π/6 + kπ
4. cscθ = √2
θ = π/4 + 2kπ
θ = 3π/4 + 2kπ
Use a calculator to solve these, on the interval 0 ≤ θ ≤ 2π:
1. cotθ = -5
θ = 3.338988213
θ = 6.480580867
I know this is wrong. The answers are 2.94 and 6.09 (rounded). But shouldn't the answers be from π-θ and 2π-θ? Theta is negative in the given equation, so shouldn't it be π+θ and 2π+θ?
2. sinθ = 0.432
θ = 0.4456092078
θ = 2.694883446
3. cotθ = -2
Same deal with this problem. shouldn't it be π+θ and 2π+θ because theta is negative?? Or have I memorized the wrong formula for each quadrant?
These are the correct answers:
θ = 2.6779
θ = 5.8195
Thank you so much!
1. Solve these equations.
tanθ = -√3
θ = 2π/3 + kπ
θ = 5π/3 + kπ
2. secθ = √2
θ = π/4 + 2kπ
θ = 7π/4 + 2kπ
3. tanθ = -√3/3
θ = 5π/6 + kπ
θ = 11π/6 + kπ
4. cscθ = √2
θ = π/4 + 2kπ
θ = 3π/4 + 2kπ
Use a calculator to solve these, on the interval 0 ≤ θ ≤ 2π:
1. cotθ = -5
θ = 3.338988213
θ = 6.480580867
I know this is wrong. The answers are 2.94 and 6.09 (rounded). But shouldn't the answers be from π-θ and 2π-θ? Theta is negative in the given equation, so shouldn't it be π+θ and 2π+θ?
2. sinθ = 0.432
θ = 0.4456092078
θ = 2.694883446
3. cotθ = -2
Same deal with this problem. shouldn't it be π+θ and 2π+θ because theta is negative?? Or have I memorized the wrong formula for each quadrant?
These are the correct answers:
θ = 2.6779
θ = 5.8195
Thank you so much!
Answers
Answered by
Steve
The first 4 are all ok
cot is negative in QII and QIV, and you are right about π±θ. But, that θ is the reference angle, which is always in QI. θ = arccot(5), not -5.
cot is negative in QII and QIV, and you are right about π±θ. But, that θ is the reference angle, which is always in QI. θ = arccot(5), not -5.
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