A hungry bear weighing 720 N walks out on a beam in an attempt to retrieve a basket of goodies hanging at the end of the beam (see the figure below). The beam is uniform, weighs 200 N, and is 7.00 m long, and it is supported by a wire at an angle of θ = 60.0°. The basket weighs 80.0 N.

Question

A hungry bear weighing 720 N walks out on a beam in an attempt to retrieve a basket of goodies hanging at the end of the beam (see the figure below). The beam is uniform, weighs 200 N, and is 7.00 m long, and it is supported by a wire at an angle of θ = 60.0°. The basket weighs 80.0 N.

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2 answers
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Answer 1

DonHo answered
9 years ago

What's the question?

Start with a free body diagram.

Post back when you get this.

Answer 2

Explain Bot answered
1 year ago

To find the tension in the wire supporting the beam, we need to consider the forces acting on the beam.

1. Weight of the bear: The bear weighs 720 N and acts downward at the center of mass of the bear.

2. Weight of the beam: The beam weighs 200 N and acts downward at its center of mass, which is also the point of support.

3. Weight of the basket: The basket weighs 80 N and acts downward at the end of the beam.

4. Tension in the wire: The tension in the wire acts upward at an angle of θ = 60.0°.

Let's break down the force components acting in the vertical and horizontal directions:

Vertical forces:
- The vertical component of the tension force in the wire will balance the sum of the vertical forces.

Horizontal forces:
- The horizontal component of the tension force in the wire will balance the horizontal forces on the beam.

Now, let's calculate the vertical forces:
- The weight of the bear acts downward with a force of 720 N.
- The weight of the beam acts downward with a force of 200 N.
- The weight of the basket acts downward with a force of 80 N.

Summing up the vertical forces:
Fy = 720 N + 200 N + 80 N

Next, let's calculate the horizontal forces:
- The horizontal component of the tension force in the wire will balance the horizontal forces on the beam.

Summing up the horizontal forces:
Fx = 0 (since there are no horizontal forces on the beam)

Now we can calculate the vertical component of the tension force:

Tension * cos(θ) = Fy

Solving for the tension:
Tension = Fy / cos(θ)

Substituting the values:
Tension = (720 N + 200 N + 80 N) / cos(60.0°)