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find the number in an A.P such that the sum of 1st and 3rd term is 12 and the product of 1st and 2nd is 24

1 answer

a + a+2d = 12
(a)(a+d) = 24

a=4, d=2

check:

4,6,8,10,...

4+8=12
4*6=24

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