Question

Calculate the mass (in grams) of sugar, C12H22O11, in 142.4 mL of a 1.39 M solution of sugar.
(atomic weights: C = 12.01, H = 1.008, O = 16.00)

Answer 1

How many mols do you have? That's M x L = ?
Then mol = grams/molar mass. You have molar mass (or can calculate it) and mols, solve for grams.

Answer 2

Sir, I don't want the answer, I'm having difficulty setting up the problem, once I can figure that out, I will try to solve. Thank you.

Answer 3

And the set up is exactly what I gave you.
Step 1 Calculate the mols you have. That is done by mols = M x L. You have M of 1.39 in the problem and you have L of 0.1424 (in the problem it is 142.4 mL and I've converted that to L).

Step 2.
You know mols = grams/molar mass. mols you have from step 1, molar mass is 180 which I assume you could calculate. That's 6*12.01+12*1.008+6*16 = 180.15 if you want it a little more accurately.
That leaves only one unknown, grams, to calculate.