Asked by Steph

(192x^2y+72x^3)-(24rxy-9rx^2)

I need help factoring completely in groups and can you please show all your work thank you
Answered by Steve
192x^2y + 72x^3 = 24x^2(8y+3x)
24rxy - 9rx^2 = 3rx(8y-3x)

The only common factor I can see is 3x, so we have

3x(64xy+24x^2-8ry+3rx)

Not sure just where you're trying to go with this

Now, if the original had been without the parentheses,

(192x^2y+72x^3)-24rxy-9rx^2

then we would have had

24x^2(8y+3x)-3rx(8y+3x)
(24x^2-3rx)(3x+8y)
3x(8x-3r)(3x+8y)
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