Asked by Jolie
On the opening night of a play at a local theatre, 895 tickets were sold for a total of $10,514. Adult tickets cost $14 each, children's tickets cost $11 each and senior citizen tickets cost $8 each. If the combined number of children and adult tickets exceeded twice the number of senior citizen tickets by 295, than how many tickets of each type were sold?
Answers
Answered by
Reiny
adults --- x
children -- y
seniors --- z
x+y+z = 895 , #1
14x +11y + 8z = 10514 , #2
translation of:
"If the combined number of children and adult tickets exceeded twice the number of senior citizen tickets by 295"
---> x+y > 2z by 295
x+y = 2z + 295
x + y - 2z = 295 #3
#1 - #3:
3z = 600
z = 200
so #1
---> x+y + 200 = 895
y= 695 - x
sub into #2:
14x + 11(695-x) +8(200) = 10514
14x + 7645 - 11x + 1600 = 10514
3x = 1269
x = 423
then y = 695 - 423 = 272
So they sold
423 adult
272 children and
200 senior tickets
checK
14(423) + 11(272) + 8(200) = 10514, YEAHHH
children -- y
seniors --- z
x+y+z = 895 , #1
14x +11y + 8z = 10514 , #2
translation of:
"If the combined number of children and adult tickets exceeded twice the number of senior citizen tickets by 295"
---> x+y > 2z by 295
x+y = 2z + 295
x + y - 2z = 295 #3
#1 - #3:
3z = 600
z = 200
so #1
---> x+y + 200 = 895
y= 695 - x
sub into #2:
14x + 11(695-x) +8(200) = 10514
14x + 7645 - 11x + 1600 = 10514
3x = 1269
x = 423
then y = 695 - 423 = 272
So they sold
423 adult
272 children and
200 senior tickets
checK
14(423) + 11(272) + 8(200) = 10514, YEAHHH
Answered by
lynn
Ticket Sales. Stacey is selling tickets to the school play. The tickets are $7 for adults and $4 for children. She sells twice as many adult tickets as children's tickets and brings in a total of $306. How many of each kind of ticket did she sell?
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