Asked by Tamera

In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginning of the reaction (at 0 minutes), 0.02 L of O2 is present. After 20 minutes the volume of O2 is 0.36 L. What is the rate of reaction?

Question 4 options:

0.001 L/min


0.017 L/min


0.022 L/min


0.330 L/min
Answered by DrBob222
dO2/dT
Answered by j
0.017
Answered by Anonymous
0.022 L/min
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