Asked by Kimberly
A block of mass is moving along the horizontal frictionless surface with a speed of 5.70 m/s. If the slope is 11.0° and the coefficient of kinetic friction between the block and the incline is 0.260, how far does the block travel up the incline? Show step by step please! Thanks!!
Answers
Answered by
bobpursley
first of all, look at the block on the incline.
The normal force is mgCosTheta
the friction force then is mu*mg*CosTheta
The portion of the block weight that is going down the incline is mgSinTheta.
initial KE=workdonegoingup slope
1/2 m v^2=(mu*mgCosTheta+mgSinTheta)d
solve all that for d.
The normal force is mgCosTheta
the friction force then is mu*mg*CosTheta
The portion of the block weight that is going down the incline is mgSinTheta.
initial KE=workdonegoingup slope
1/2 m v^2=(mu*mgCosTheta+mgSinTheta)d
solve all that for d.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.